Lakes / Indiana / LaGrange County / Lake of the Woods
Lake of the Woods, LaGrange County, Indiana
132.76 acres
Surface Area
Where It Sits, and How Deep It Goes
Locator - Indiana
41.55 degrees N, 85.20 degrees W - LaGrange County. State and county outlines drawn from Census boundary data; the lake marker is placed by its USGS National Hydrography Dataset coordinates, not by eye. Schematic - not a survey map.
How Lake of the Woods Stacks Up
- Larger than 72% of the 425 lakes counted in Indiana.
- About 32 miles from Fort Wayne, as the crow flies.
Lakes Nearby
| Lake | County | Distance | Surface Area |
|---|---|---|---|
| McClish Lake | Steuben | 0.5 mi | 35.96 acres |
| Big Long Lake | LaGrange | 2.0 mi | 392.29 acres |
| Mud Lake | LaGrange | 2.2 mi | 40.51 acres |
| Limekiln Lake | Steuben | 2.2 mi | 27.84 acres |
| Big Turkey Lake | Steuben | 3.0 mi | 469.53 acres |
| Pretty Lake | LaGrange | 3.3 mi | 185.12 acres |
Straight-line distance between lake centers.
Facts and Figures
Questions About Lake of the Woods
How Big Is Lake of the Woods?
Lake of the Woods covers 132.76 acres in LaGrange County, Indiana.
What Is the Largest Lake in LaGrange County?
Dallas Lake is the largest lake in LaGrange County, at 407.12 acres.
Largest Lakes in Indiana
| # | Lake | County | Surface Area | Max Depth |
|---|---|---|---|---|
| 1 | Monroe Lake | Monroe | 11,112.45 acres | - |
| 2 | Patoka Lake | Orange | 9,120.83 acres | - |
| 3 | Brookville Lake | Franklin | 4,364.22 acres | - |
| 4 | Lake Wawasee | Kosciusko | 3,426.28 acres | - |
| 5 | Broad Pond | Gibson | 2,941.52 acres | - |
All 425 Indiana lakes ranked by surface area
Sources: USGS National Hydrography Dataset (The National Map) lake data (ID 155641499). Verified October 30, 2026.