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Lakes / South Dakota / Roberts County / Indian Slough

Indian Slough, South Dakota

29.16 acres
Surface Area

Where It Sits, and How Deep It Goes

Locator - South Dakota

Sioux FallsPierreIndian SloughRoberts Co.

45.92 degrees N, 97.00 degrees W - Roberts County. State and county outlines drawn from Census boundary data; the lake marker is placed by its USGS National Hydrography Dataset coordinates, not by eye. Schematic - not a survey map.

How Indian Slough Stacks Up

Lakes Nearby

LakeCountyDistanceSurface Area
Dobberstien SloughRoberts4.7 mi73.14 acres
Knebel SloughRoberts8.8 mi32.87 acres
Cottonwood LakeRoberts10 mi597.25 acres
Lake BdesakaRoberts16 mi149.99 acres
Mud LakeMarshall18 mi165.07 acres
Greys LakeMarshall18 mi184.34 acres

Straight-line distance between lake centers.

Facts and Figures

Waterbody ID126211610
CountyRoberts
Coordinates45.9180, -97.0027

Questions About Indian Slough

How Big Is Indian Slough?

Indian Slough covers 29.16 acres in Roberts County, South Dakota.

What Is the Largest Lake in Roberts County?

Lake Traverse is the largest lake in Roberts County, at 10,747.48 acres.

Largest Lakes in South Dakota

#LakeCountySurface AreaMax Depth
1Lake OaheDewey309,912.57 acres-
2Lake Francis CaseCharles Mix82,166.92 acres-
3Lake SharpeHughes58,419.67 acres-
4Lewis and Clark LakeBon Homme25,141.99 acres-
5Lake ThompsonKingsbury13,887.93 acres-

All 533 South Dakota lakes ranked by surface area

Sources: USGS National Hydrography Dataset (The National Map) lake data (ID 126211610). Verified October 30, 2026.